Please help me do question 10 :)

A: sin(55.13+22.62) = .969

B: Cos(55.13-22.62) = .861

C: sin(2*55.13) = .96

D: cos(2*55.13) = -.28

E: tan(55.13+22.62) = 3.9375

F: cot=1/tan= 1/tan(55.13-22.62)= 1.6969

Step-by-step explanation:

I would like to preface this by saying that my trig is probably rusty so maybe double check my work. I will try to overexplain it so you can easily spot any errors I may make

To solve for x we know that sin(x)=4/5

we can solve for x by using the arc sin

This means that x=arcsin(4/5) which gives me around x=53.13

We can then use the same process for y but with 5/13

so arcsin(5/13) gives us around y=22.62

Then it's just a matter of plugging everything in

A: sin(55.13+22.62) = .969

B: Cos(55.13-22.62) = .861

C: sin(2*55.13) = .96

D: cos(2*55.13) = -.28

E: tan(55.13+22.62) = 3.9375

F: cot=1/tan= 1/tan(55.13-22.62)= 1.6969

the answer is 0.071

good luck! : d

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.