Find a polynomial f (x) of degree 3 with real coefficients and the following zeros. -3, 1+2i
f(x) =
x
?

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Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*