What is the equation of the line that passes through point(-5,-3) and has a slope of -1

In this problem, we will be using the point-slope formula.

y - y₁ = m(x - x₁)

The point we are given, (-5, -3), represents (x₁, y₁) in the formula

and our slope which in this case is -1 represents our m.

Now let's plug all our information into the point-slope formula.

So we have y + 3 = -1(x + 5).

Remember that minus a negative means plus a positive

which is why I changed y - (-3) to y + 3 and the same for the x + 5.

So we have y + 3 = -1(x + 5).

Now distribute the -1 to get y + 3 = -x - 5

Now move the 3 to the right side by subtracting 3 to get y = -x - 8.

Now add x to both sides to get x + y = -8.

So the equation of this line in standard form is x + y = -8.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

answer: it's upside down and i can't read it

step-by-step explanation: