Mr. Harris has batteries for his calculators. If b represents the number of batteries and c represents his calculators, how many batteries does Mr. Harris have?
b= 4c
3c = -2b + 44
A 4 batteries
B 7 batteries
13 batteries
16 batteries

These are simultaneous equations, and you can solve this by using the substitution method:

b = 4c
3c = -2b + 44

3c = -2(4c) + 44
3c = (-2 x 4c) + 44
3c = -8c + 44

11c = 44
c = 44/11
c = 4

b = 4c
b = 4(4)
b = 4 x 4
b = 16

Therefore, Mr. Harris has 16 batteries.

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