Joey's father stops at the gas station to buy gas. the car has a 16-gallon tank, and the fuel gauge says there is 3/8 of a tank of gas. if joey's father buys 6 gallons of gas, what fraction of the tank will car's fuel gauge read?

The fraction of the tank after adding 6 gallons of gas will be 6/8 of the tank

Step-by-step explanation:

Joey's father stops at the gas station to buy gas.

The car has a 16 gallons tank, and the fuel gauge says there is 3/8 of a tank of gas.

The car has (3/8)*16 gallons, it means 48/8 = 6 Gallons.

If Joey's father buys 6 gallons. The car will have the previous volume plus the 6 gallons.

6 + 6 = 12 gallons.

The new volume of gas in the tank will be 12 gallons.

Finally, we can find the fraction of the total volume which should be 16 gallons.

F = 12/16 = 6/8

The fraction of the tank read will be 6/8 after adding 6 gallons.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.