A farm has 6 chickens, 4 ducks, 2 pigs and 4 cows. If an animal is chosen at random, find P(Cow | 2 legs)

P(Cow | pig) = 1/2

Step-by-step explanation:

Given that there are;

6 chickens

4 ducks

2 pigs

To find the probability that an animal chosen at random is a cow or pig.

Recall that probability is the ratio of the number of possible outcome to the total number of outcome . As such, the probability of picking a

cow

P(cow) = 4/(6 + 4 + 2)

= 4/12

Pig

P(Pig) = 2/(6 + 4 + 2)

= 2/12

The probability

P(Cow | pig) = 4/12 + 2/12

= 6/12

= 1/2

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

it has the same slope and a different y-intercept

hope this : )