Find each sum or difference. 1. (6x2 - 4)+(- 2x +9)
2. g - 292 +59 + 6) -(g2 + 29)
3. (4 + 2a- 2a) - (3a2 - 8a + 7)
4. (8y - 4y2) + (3y - 9y2)
5. (- 4z- 27 + 8) – (42? + 3z2 – 5)
6. (-3d? - 8 + 2d) + (4d - 12 + d)
7. (y + 5) + (2y + 4y2 - 2)
8. (3n- 5n+ n?) - (-8n2 + 3n)

4444444444444 i think

2425

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)