The population of a city can be modelled by the function P(x) = -22.5x2 +428x + 1100, where x is the number of years since
1990. According to the model, when will the population be the highest?

1991
1999
2002
2005

1

Population model

P=375.55e^(-0.01052t)

we are required to find t when p=300000.  

substituting the values in formula and solving for t we get:

300000=375.55e^(-0.01052t)

this will give us

798.828385=e^(-0.01052t)

getting the natural log of both sides will be:

6.683146136=0.01052t

t=635.28~635

Given that t=0 in 1990, the population would be 300000 in the years 2625

Step-by-step explanation:

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: