Based on the following calculator output, determine the inter-quartile range of the dataset. \text{1-Var-Stats}1-Var-Stats
\bar{x}=125.857142857
x
ˉ
=125.857142857
\Sigma x =881Σx=881
\Sigma x^2 =112997Σx
2
=112997
Sx =18.7832245317Sx=18.7832245317
\sigma x =17.38988681σx=17.38988681
n =7n=7
\text{minX} =91minX=91
\text{Q}_1 =116Q
1

=116
\text{Med} =128Med=128
\text{Q}_3 =140Q
3

=140
\text{maxX} =150maxX=150

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.