The figure below shows a square ABCD and an equilateral triangle DPC: D
Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:
Statements
In triangles APD and BPC; DP = PC
In triangles APD and BPC; AD = BC
Justifications
Sides of equilateral triangle DPC are equal
Sides of square ABCD are equal
Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 30°
Triangles APD and BPC are congruent SAS postulate
Which of the following completes Ted's proof? (1 point)
O In square ABCD; angle ADC= angle BCD
O In square ABCD; angle ADP= angle BCP
O In triangles APD and BPC; angle ADC
angle BCD
O In triangles APD and BPC; angle ADP = angle BCP

When the solutions to each of the two equations below are graphed in the xy-coordinate plane, the graphs of the solutions intersect at two places. write the y-cordninates of the points of intersection in the boxes below in order from smallest to largest. y=2x y=x^2-3

Jermaine has t subway tokens. karen has 4 more subway tokens than jermaine. raul has 5 fewer subway tokens than jermaine. which expression represents the ratio of karen's tokens to raul's tokens

(01.03 mc) which of the following is a step in simplifying the expression x multiplied by y to the power of 2 over x to the power of negative 3 multiplied by y to the power of 3, the whole to the power of negative 4. select one: a. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 7 multiplied by y to the power of negative 1. b. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of 12 multiplied by y to the power of negative 12. c. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of negative 3 multiplied by y to the power of 3. d. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 3 multiplied by y to the power of 3.