What is the probability that a number chosen at random from the 2, 4,5 and 6 times tables (up to the 12th multiple) is either a multiple of 3, prime or a
square number?

Step-by-step explanation:

2456

481012

6121518

8162024

10202530

12243036

14283542

16324048

18364554

20405060

22445566

24486072

I have set this table up in a spreadsheet and colored in the squares as they appear in the table above. I have not counted any number as a member of 2 categories twice. An example would be 36 which is a multiple of 3 and a perfect square.

I have answered the question as though the question took on the properties of a dart board: you through a dart and whatever you hit is counted either as prime, a multiple of 3 or a perfect square

That said, there are

primes:                    2

multiples of 3:       24

Perfect squares:      4

Total number of choices: 12*4 = 48

Probability: 30 / 48 = 5/8 or 0.625

If you are supposed to use some other method of counting, please leave a note.

1696 hundred thousand

step-by-step explanation:

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540