Integrate y = (2x + 2)^5 with respect to x

∫ (2x + 2)⁵ dx

Substitute u = 2x + 2, so that du = 2 dx. Then

∫ (2x + 2)⁵ dx = ∫ u ⁵ (du/2) = 1/2 ∫ u ⁵ du

Use the power rule:

1/2 ∫ u ⁵ du = 1/2 (1/6 u ⁶) + C = 1/12 u ⁶ + C

Replace u to get the antiderivative back in terms of x :

∫ (2x + 2)⁵ dx = 1/12 (2x + 2)⁶ + C

and the result can be simplified a bit as

(2x + 2)⁶ = 2⁶ (x + 1)⁶

→   ∫ (2x + 2)⁵ dx = 2⁴/3 (x + 1)⁶ + C = 16/3 (x + 1)⁶ + C

step-by-step explanation: examine the two-step equation.

−  

7

4

+  

x

4

= 2

which property of operations allows you to add the same constant term to both sides?

multiplication property of equality

division property of equality

addition property of equality

subtraction property of equality

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation: