Mathematics, 20.01.2021 18:20 salterappraisal5757
OM is height of AOB, and ON is height of DOC. OM=ON (point O is on line AC). AM=4.2cm, DN=2.6cm. find CD.
(see the picture).
please explain
Answers: 2
![We\ are\ given:\\OM\ is\ altitude\ of\ \triangle AOB\\ON\ is\ altitude\ of\ \triangle DOC\\Now,\\Lets\ only\ focus\ on\ the\ interior\ triangles\ inside\ the\ two\ above\ triangles.\\They\ are:\\\triangle OMA\ and\ \triangle ONC.\\\\We\ observe\ that:\\\angle AMO=90[As\ it\ is\ the\ altitude\ of\ \triangle AMO]\\\angle ONC=90[As\ it\ is\ the\ altitude\ of\ \triangle ONC]\\Hence,\\\angle AMO= \angle ONC=90\\\\](/tpl/images/1048/4428/54109.png)
![Hence,\\AM=NC [Corresponding\ Parts\ of\ Congruent\ Triangles]\\We\ can\ observe\ that,\\CD=DN+NC\\Hence,\\DN=2.6\ cm [Given]\\NC=AM=4.2\ cm [Proven]\\Hence,\\DC=2.6+4.2=6.8\ cm](/tpl/images/1048/4428/f12cb.png)
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OM is height of AOB, and ON is height of DOC. OM=ON (point O is on line AC). AM=4.2cm, DN=2.6cm. fin...
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