Write an equation of a line that is parallel to y=3x-2 and runs through the point (1,6)

y=3x+3

Step-by-step explanation:

If equations of lines are parallel, their slopes are the same. Therefore, we can sub '3' in for the slope value in y=mx+c to get y=3x+c.

Sub in the point:

6=3(1)+c

c=6-3=3

ANS: y=3x+3

y = 3x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 2 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, so

y = 3x + c ← is the partial equation

To find c substitute (1, 6) into the partial equation

6 = 3 + c ⇒ c = 6 - 3 = 3

y = 3x + 3 ← equation of parallel line

13875138answer:

step-by-step explanation:

use a calculator!

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.