A bag contains only blue and green counters. If there were three times as many blue counters and the original numbers of
green counters, the total number of counters in the bag would be 62.
If there were twice as many green counters and the original number of blue
counters, the total number of counters in the bag would be 59.
How many of each colour are in the bag?
Do not use trial and improvement.
You must show your working.
Give your answer in the form of coordinates:- (Blue, Green) *
(4 Points)
(15

idk lol

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

step-by-step explanation: