I need help fast pls

y < 4x-1

Step-by-step explanation:

Slope intercept form is y = mx + c

c is where it cross the vertical line (the y-axis)

This happens at -1 so c is -1.

m is the slope

This is how far up it goes per unit along.

It goes from y=-1 to y=3 from x=0 to x=1

(0, -1) to (1, 3)

It goes 4 up per 1 along, 4/1 = 4 so m = 4

Final form of the line is y = 4x - 1

To find the inequality try (0, 0):

4(0) - 1 = -1

comparing y=0 to -1 we know 0 is bigger, BUT we don't want (0,0) to be in the region so we say

y < 4x - 1

You could do this for any point, like (1,1):

4(1) - 1 = 3

1 < 3 and we want this to be in the range so we once again say

y < 4x - 1

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180