Tim’s age is nine more than his sister, Jill. Twice his age added to twice Jill’s age is 330.

jill age is 78 and tim's age is 87

Step-by-step explanation:

let jill age be x then, tim's age is 9+x

by the question,

2(9+x) + 2x = 330

or,18 + 2x + 2x = 330

or,4x = 330-18

or, x = 312÷4

x = 78

9+x= 9+78=87

i dont know sorry

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)