What is an equation of the line that passes through the point (8, 2) and is parallel to the line 5x – 4y = 36?

Step-by-step explanation:

5x - 4y = 36

4y = 5x - 36

y = 1.25x - 9

Since this line has a slope of 1.25, the parallel line will also have a slope of 1.25.

=> y = 1.25x + c

When x = 8, y = 2.

=> (2) = 1.25(8) + c

=> 2 = 10 + c, c = -8

Hence the line equation is y = 1.25x - 8.

When the point is (8,2) and slope is 5/4

Putting the value of c=-8, we get

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's