Carson measured a line to be 2.2 inches long. If the actual length of the line is 2.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

1010: 3030

is it i think

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

i believe the answer is c.

i think the answer would be c