Given the transformation f(x, y)=(x+3, y−6), determine the value of the range for each point in the domain. 1. domain:(−7, −10) range: ( , )

2. domain: (10, −9) range: ( , )

3. domain: (6, 3) range: ( , )

PLZ HELP !!

In this section, we study how the graphs of functions change, or transform, when certain specialized

modifications are made to their formulas. The transformations we will study fall into three broad

categories: shifts, reflections and scalings, and we will present them in that order. Suppose the

graph below is the complete graph of a function f.

(0, 1)

(2, 3)

(4, 3)

(5, 5)

x

y

1 2 3 4 5

2

3

4

5

y = f(x)

The Fundamental Graphing Principle for Functions says that for a point (a, b) to be on the graph,

f(a) = b. In particular, we know f(0) = 1, f(2) = 3, f(4) = 3 and f(5) = 5. Suppose we wanted to

graph the function defined by the formula g(x) = f(x) + 2. Let’s take a minute to remind ourselves

of what g is doing. We start with an input x to the function f and we obtain the output f(x).

The function g takes the output f(x) and adds 2 to it. In order to graph g, we need to graph the

points (x, g(x)). How are we to find the values for g(x) without a formula for f(x)? The answer is

that we don’t need a formula for f(x), we just need the values of f(x). The values of f(x) are the

y values on the graph of y = f(x). For example, using the points indicated on the graph of f, we

Step-by-step explanation:

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step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w