!! Please, help me with this! Thank you!! Write the equation in standard form of the circle whose diameter has endpoints of (-2, 4) and (8, -6).

A.(x - 3)^2 + (y + 1)^2 = 50
B.(x - 5)^2 + (y - 5)^2 = 50
C.(x - 3)^2 + (y + 1)^2 = 200

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .