Bacteria growth. A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. At the end of 3 h there are 10,000 bacteria. At the end of 5 h there are 40,000 bacteria. How many bacteria were present initially

1250 bacteria

Step-by-step explanation:

The formula for Exponential Growth is given as:

P(t)= Poe^rt

Where

P(t) = Population after time t

Po = Initial Population

r = growth rate

t = time

Hence, solving for the above question , we have to find Po

Making Po the subject of the formula

Po = P(t)/e^rt

Step 1

Find the Exponential growth rate

At the end of 3 h there are 10,000 bacteria.

Hence:

Po = 10000/e^3r Equation 1

At the end of 5 h there are 40,000 bacteria.

Po = 40000/e^5r Equation 2

Equating both equations together,

10000/e^3r = 40000/e^5r

Hence:

e^5r/e^3r = 40000/10000

e^2r = 4

Take the In of both sides

In (e^2r) =In 4

2r= In 4

r = In 4/2

r = In 2

Step 2

Solve for Po(Initial Population)

Using Equation 2

Po = 40000/e^5r Equation 2

r = In2

Po = 40000/e^5 × In 2

Po = 40000/2⁵

Po = 1250 bacteria.

Therefore, they was 1250 bacteria initially

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

answer: a) 56% women

b)44% men

step-by-step explanation: