In each of the months June, July, and August, the number of accidents occurring in that month is modeled by a Poisson random variable with mean 1. In each of the other 9 months of the year, the number of accidents occurring is modeled by a Poisson random variable with mean 0.5. Assume that these 12 random variables are mutually independent. Calculate the probability that exactly two accidents occur in July through Novembe

Step-by-step explanation:

From the question we are told that

Sample size n=3

Sample mean 1  

Sample mean 2

Generally the Probability that 2 accidents occurs from July to August is mathematically given by

Generally the probability that 2 deaths occurs from September through November is mathematically given by

Therefore

Total Mean accidents

Generally the probability of  two accident per month is mathematically given by

Therefore the probability of having  2 accidents from July through to November is

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.