Find axis of symmetry f(x)=2(x-5)(x+9)

x = -2

Step-by-step explanation:

f(x) = 2( x^2 +9x -5x - 45)

f(x) = 2(x^2 + 4x - 45)

f(x) = 2x^2 +8x -90

axis of symmetry formula: x = -b / 2a

x = -(8) / 2(2)

x = -8 / 4

x = -2

*you can also graph the equation on a graphing calculator and find the middle of the parabola

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)