Find the discriminant of the equation and give the number and type of solutions of the equation 4x^2+2x-5=0 Please help fast!!

The answer is 84.

Step-by-step explanation:

The given equation is

4x*2 + 2x -5 = 0

Here a= 4, b= 2, c= -5

Since Discriminant= b*2 -4ac

Putting values

Discriminant= (2)*2 - 4(4)(-5)

= 4 + 80

= 84

Since our Discriminant(84) is >0 and is not a perfect square so the roots of the given equation are unequal and irrational(real).

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct