There are 90 passengers on a commuter flight from SFO to LAX, of whom 27 are traveling on business. In a random sample of five passengers, use the binomial model to find the approximate hypergeometric probability that there is at least one business passenger.

0.8401 = 84.01% probability that there is at least one business passenger.

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this question:

Samples of 5, so

90 passengers, so

27 traveling on businnes, so

Probability that there is at least one business passenger.

Either none are on business, or at least one is. The sum of these probabilities is 100% = 1.

Probability of none on business:

Probability of at least one business passenger:

0.8401 = 84.01% probability that there is at least one business passenger.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

probably the last option

step-by-step explanation: