A motorboat takes hours to travel kilometers going upstream. The return trip takes hours going downstream. What is the rate of the boat in still water and what is the rate of the current

Rate of boat in still water = 56 km per hour

Rate of the current = 8 km per hour

Step-by-step explanation:

This question is incomplete; to understand how to solve these questions let the question is,

A motorboat takes 4 hours to travel 192 km going upstream. The return trip takes 3 hours going downstream. What is the rate of the boat in still water and what is the rate of current.

Let the rate of current = u km per hour

And the rate of boat in still water = v km per hour

Then going upstream, rate of the boat = Rate of the boat in still water - Rate of current

= (v - u) km per hour

Similarly, going downstream, rate of the boat = Rate of boat in still water + Rate of current

= (v + u) km per hour

Since, the boat takes 4 hours upstream,

By using the formula,

Rate =

Distance traveled = Rate × Time

For upstream,

192 = 4(v - u)

v - u = 48 ------(1)

For downstream,

192 = 3(v + u)

v + u = 64 ------(2)

By adding equation (1) and (2),

(v - u) + (v + u) = 48 + 64

2v = 112

v = 56 km per hour

From equation (1),

56 - u = 48

u = 56 - 48

u = 8 km per hour

Rate of boat in still water = 56 km per hour

Rate of the current = 8 km per hour

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~