In a simple electric circuit, Ohm's law states that V = IR, where V is the voltagein volts, I is the current in amperes, and R is the resistance inohms. Assume that, as the battery wears out, the voltage decreasesat 0.01 volts per second and, as the resistor heats up, theresistance is increasing at 0.02 ohms per second. When theresistance is 200 ohms and the current is 0.03 amperes, at whatrate is the current changing?