Someone who can answer this is getting 20+ up false answer with no effort will be reported. Two ships leave a port at the same time and travel in opposite directions. The speed
of the faster ship at x km/h is 8 km/h more than that of the slower ship at y km/h.
At the end of 2.5 days, the two ships are 4,320 km apart.

1) Find the speed of each of the two ships.

2)Calculate how much longer it would take the slower ship to reach a destination 1,780
km away than the faster ship if they leave the port at the same time. (Give your
answer in hours and minutes.)

it’s the first one your welcome

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus