F(x) = 3r2 + 12x + 5 What is the value of the discriminant of f?
D
How many distinct real number zeros does
f(x) have?

The value of the discriminant is 84.

i.e. b²- 4ac =  84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

Step-by-step explanation:

We know that the discriminant of the quadratic equation ax²+bx+c=0 is equal to b²- 4ac.

We also know that:

We are given

f(x) = 3x² + 12x + 5

comparing with the quadratic function ax²+bx+c=0

a = 3, b = 12, c = 5

Discriminant = b²- 4ac

                     = (12)²-4(3)(5)    ∵ a = 3, b = 12, c = 5

                     = 144 - 60

                     = 84

Thus, the value of the discriminant is:  84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b