See question in image.
Please show workings .

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim ( h tends to zero )

      = lim ( h to 0 )

     = lim ( h to zero )

     = lim ( h to zero )

     = ( lim h to 0 )

     = ( lim h to 0 )

     = lim ( h to 0 ) - ← cancel h on numerator/ denominator of both

     = lim( h to 0 ) 2(2x + h) - 1 ← let h go to zero

f'(x) = 4x - 1

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: