A committee must be formed with 5 teachers and 4 students. If there are 6 teachers to choose from, and 15 students, how many different ways could the committee be mad?

8190 ways

Step-by-step explanation:

Given

Selection

Required

Number of ways of selection

4 students can be selected from 15 students in:

Similarly.

5 teachers can be selected from 6 teachers in:

So, the required number of selection is:

Apply combination formula:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

yes

step-by-step explanation:

yes