Mathematics, 16.01.2021 23:20 cpcoolestkid4

Find the value of the polynomial 2x^3y^3+3xy-3x^3y^3+x^2y-xy+2x^2y for x=-1 and y=2

Answers: 1

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Answer from: haha396

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Step-by-step explanation:

Step 1: Define

2x³y³ + 3xy - 3x³y³ + x²y - xy + 2x²y

x = -1

y = 2

Step 2: Evaluate

Substitute: 2(-1)³(2)³ + 3(-1)(2) - 3(-1)³(2)³ + (-1)²(2) - (-1)(2) + 2(-1)²(2)Exponents: 2(-1)(8) + 3(-1)(2) - 3(-1)(8) + 1(2) - (-1)(2) + 2(1)(2)Multiply: -16 - 6 + 24 + 2 - (-2) + 4Simplify: -16 - 6 + 24 + 2 + 2 + 4Subtract: -22 + 24 + 2 + 2 + 4Add: 2 + 2 + 2 + 4Add: 4 + 2 + 4Add: 6 + 4Add: 10

Answer from: Quest

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

Answer from: Quest

idk

step-by-step explanation:

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Find the value of the polynomial 2x^3y^3+3xy-3x^3y^3+x^2y-xy+2x^2y for x=-1 and y=2...