Two hikers are miles apart and walking toward each other. They meet in hours. Find the rate of each hiker if one hiker walks mph faster than the other. The speed of the slow hiker is nothing mph, and the speed of the fast hiker is nothing mph.

Complete question : Two hikers are 33 miles apart and walking toward each other. They meet in 5 hours. Find the rate of each hiker if one hiker walks 2.2 mph faster than the other. The speed of the slow hiker is nothing mph, and the speed of the fast hiker is nothing mph.

2.2 mph ; 4.4 mph

Step-by-step explanation:

Given that :

Total distance apart = 33

Time taken = 5 hours

Rate of slow hiker = x

Rate of fast hiker = x + 2.2

Speed (rate) = distance / time

Distance = speed * time

Distance covered by fast hiker + distance covers by slow hiker

(x + 2.2)*5 + 5x = 33

5x + 11 + 5x = 33

10x = 33 - 11

10x = 22

x = 22 / 10

x = 2.2

Rate of slow hiker = 2.2 mph

Rate of fat hike = x + 2.2 = 2.2 + 2.2 = 4.4 moj

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

answer: i think it is (1,-2)