A fish tank has 150 gallons of water and is being drained at a rate of 1/2 gallon each second. A fish tank has 120 gallons of water and is being filled at a rate of 1/4 gallon each second. After how many seconds will the ywo fish tanks have the same amount of water?

40! Seconds

Step-by-step explanation:

Calculation for After how many seconds will the two fish tanks have the same amount of water

First step

Based on the information given let the equation be :

150-1/2x=120+1/4x

Second step

Now let solve for x which means that x will be the number of second by multiplying both side by 4

4(150-1/2x)=4(120+1/4x)

=600-2x=480+x

Third step

Let Add 2x on both side

600=480+3x

Third step

Let Subtract 480 on both side

600-480=480-480+3x

120=3x

Last step is to divide both side by 3

120/3=3x/3

40=x

Hence:

x=40 seconds

Therefore After 40 seconds the two fish tanks will have the same amount of water.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !