What are the zeros of the polynomial y = (3x − 1)(x + 2)(2x + 1)? (4 points) negative two comma negative start fraction one over two end fraction comma start fraction one over three end fraction negative two comma negative start fraction one over two end fraction comma negative start fraction one over three end fraction 3, −2, 2 two comma start fraction one over two end fraction comma negative start fraction one over three end fraction

1/3, -2 and -1/2

Step-by-step explanation:

Given the polynomial function y = (3x − 1)(x + 2)(2x + 1)

The zeros of the function occurs at when y = 0

The expression becomes;

(3x − 1)(x + 2)(2x + 1) = 0

3x - 1 = 0

3x  = 1

x  = 1/3

Also

x = x+2

x = 0-2

x = -2

2x+ 1 = 0

2x = 0-1

2x = -1

x = -1/2

Hence the zeros of the polynomial are 1/3, -2 and -1/2

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation: