A builder was building a fence. In the morning, he worked for 2/5 of an hour. In the afternoon, he worked for 9/10 of an hour How many times as long as in the morning did he
work in the afternoon?

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q

to find perimiter, add all the sides.

60 5/6 + 54 1/3 + 59 1/3 + 56 1/6.

goup like terms:

(60 5/6 + 56 1/6) + ( 54 1/3 + 59 1/3) = 117 + 113 2/3

56 + 60 =   116. 5/6 + 1/6 = 6/6 = 1/ 116 + 1 = 117

54 + 59 = 13. 1/3 + 1/3 =2/3. 13 + /3 = 113 2/3    

117 + 113 2/3 = 230 2/3

answer: 230 2/3

the coach can choose 4 members to send to competition in 1680 ways. the correct answer between all the choices given is the second choice. i am hoping that this answer has satisfied your query and it will be able to you in your endeavor, and if you would like, feel free to ask another question.