Mathematics, 15.01.2021 21:00 miami158999
Given the function g(x)=41x^3+a for some constant a, which describes the inverse function g^-1(x)
Answers: 3
![g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}](/tpl/images/1039/8187/12d5c.png)
and 
values switched from the original function. Therefore, simply switch 
![x=41y^3+a,\\x-a=41y^3,\\\frac{x-a}{41}=y^3,\\y=\sqrt[3]{\frac{x-a}{41}}](/tpl/images/1039/8187/3036d.png)
.![\fbox{$g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}$}](/tpl/images/1039/8187/3374b.png)
.
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Given the function g(x)=41x^3+a for some constant a, which describes the inverse function g^-1(x)...
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