A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length. What is the greatest numberof 15-inch pieces the seamstress can cut from 5
of these rolls of ribbon?

36

Step-by-step explanation:

One roll length is = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

There are 5 rolls

Total length of 5 rolls = 108 * 5 = 540

540 divided by 15

540/15 = 36

The greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36.

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7