The equation of line t is y = -2x + 9. Perpendicular to line t is line u, which passes through the point (-10, 4). What is the equation of line u?
Write the equation in slope-intercept form. Write the numbers in the equation as proper
fractions, improper fractions, or integers.

Equation of line u in slope-intercept form is:

Step-by-step explanation:

Equation of line t : y = -2x + 9.

We need to find equation of line u, which is perpendicular to line t and passes through point (-10,4)

The equation must be in slope-intercept form.

The general equation of slope-intercept form is: where m is slope and b is y-intercept

Finding Slope:

If two lines are perpendicular, their slopes are opposite i.e

Slope of line t: y=-2x+9 we get m =-2 (Comparing with general form y=mx+b, we get m =-2)

Slope of line u:

So, we get Slope of line u: m=

Finding y-intercept:

Using slope m= and point(-10,4) we can find y-intercept

Equation of line u:

So, equation of line u, having slope m= and y-intercept b=9, we get:

So, Equation of line u in slope-intercept form is:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

i think asking google will you get the answer to that question