The lengths of the sides of a triangle are consecutive even integers. one fourth of the perimeter is one less than the length of the shortest side. find the perimeter of the triangle. Please help xD

Step-by-step explanation:

Let the shortest side be x, the other sides are x + 2 and x + 4

Perimeter is:

It is given that:

Substitute and solve for x:

Perimeter is:

HERE,

the lengths of the sides of a triangle are consecutive even integers.

If one angle=a

other are=(a+2) and (a+4)

So,

perimeter(p) =a+a+2+a+4=3a+6

But,

one fourth of the perimeter is one less than the length of the shortest side.

so,

According to the question,

so,

Perimeter (p)=3×10+6=30+6=36

perimeter of the triangle is 36 .

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc