Determine the center and radius of the following circle equation: x^2+y^2-8x+6y-75=0 x 2 +y 2 −8x+6y−75=0 Center: \big(( , \big)) Radius:

Compare x^2 +y^2-8x-6y=75 with the general circle equation x^2+y^2 -2ax-2by+c=0

-2a =-8 And -2b=-6

a=4 b=3

c=-75

To find the radius use the equation

r^2=a^2+b^2-c

r^2=4^2+ 3^2-(-75)

r^2=25+75=100

r=10(radius is always positive)

Hence the center is (4,3) and radius 10

Step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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