(100 POINTS PLUS BRAINIEST IF CORRECT I NEED HELP FAST) The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. There are 9 desired outcomes. What is the probability of rolling an even number first and an odd number second?
StartFraction 1 over 9 EndFraction
StartFraction 1 over 6 EndFraction
One-fourth
One-half

The image is missing, we have attached the image.

The of getting an even number in first and an odd number second is 1/4 or 0.25

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

(2,1)(2,3)(2,5)(4,1)(4,3)(4,5)(6,1)(6,3)(6,5)

So the total number of outcomes = 9

Now according to the formula of probability, which is;

P(E)= total number of possible outcomes/total number of outcomes

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)= 9/36 = 1/4 =0.25

Hence The of getting an even number in first and an odd number second is

1/4 or 0.25.

Hope this help

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)