Point S has the coordinates (6, –4). On a coordinate plane, point R is 6 units to the left and 4 units up. Point S is 6 units to the right and 4 units down. Point T is 6 units to the left and 4 units down. Point U is 6 units to the right and 4 units up. Which point on the graph shows the reflection of point S across the y-axis? R A

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

hi there!

not proportional because the 42 does not go into 120 and 3 does not go into 8.

correct proportion: $40/1 ticket.

the reason i say this is because 40/1 is simplified and it evenly goes into 120/3.

hope this : )

answer: 24

step-by-step explanation:

7x2=14

5x2=10

10+14=24