What is the equation in slope-intercept form of the line that passes through the point (12, 5) and is perpendicular to the line represented by y=34x−8?

The equation in slope-intercept form of the line that passes through the point (12, 5) and is perpendicular to the line is:

Step-by-step explanation:

We know the slope-intercept form of the line equation

where m is the slope and b is the y-intercept

Given the line

comparing with the slope-intercept form of the line equation

The slope m = 34

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:  

slope = m = 34

Thus, the slope of the the new perpendicular line = – 1/m = -1/34 = -1/34

Using the point-slope form

where m is the slope of the line and (x₁, y₁) is the point

substituting the values of slope = -1/35 and the point (12, 5)

Add 5 to both sides

Therefore, the equation in slope-intercept form of the line that passes through the point (12, 5) and is perpendicular to the line is:

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°