1. You are on the beach in Wasaga Beach, Ontario. At 2:00 PM on June 15th, the tide is high. At that time you find that the depth at the end of the
pier is 1.5 meters. At 8:00 pm the same day, the tide is low, and you find
that the depth of the water is 1.1 meters. Assuming the depth of the water
varies sinusoidally with time:
a) Identify the key features of the sinusoidal function, and use them to
sketch a graph showing two tide cycles.
b) Determine an equation to represent the tide in Wasaga Beach.
c) Determine the height of the water at 11:00 PM the same day.
d) Determine the first two times after high tide where the height of the water
is 1.2 metres.

i will pick c put check it over to be sure

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0