Ur amazing if u understand bearings

Sam's "bearing" is simply the direction in which he's moving, which is the angle made with due East.

From point A to point B, his bearing is 335°, and from point B to C, his bearing is 45°. In both cases, the angle is made with due East from the second point. See the sketch for a rough approximation of this. Note that it is not to scale.

To get it into scale, you have to compute the distances traveled along each bearing.

• Moving at 6 km/h for 20 min = 1/3 h would cover a distance of

(6 km/h) • (1/3 h) = 2 km

• Moving at 10 km/h for 15 min = 1/4 h would mean a distance of

(10 km/h) • (1/4 h) = 2.5 km

In your sketch, 1 cm should represent 500 m = 0.5 km, so the arrow from A to B should have a length of 4 cm, while the arrow from B to C should have a length of 5 cm.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!