Which expression is equivalent to the given expression?
(-6ab)2

B. 36a^2b^2

Step-by-step explanation:

1. Apply exponent rule: (-a)^n = a^n, if n is even

(-6ab)^2 = (6ab)^2

(6ab)^2

2. Apply exponent rule: (a × b)^n = a^nb^n

(6ab)^2 = 6^2a^2b^2

6^2a^2b^2

3. 6^2 = 36

36a^2b^2

In other words, your answer is B.

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.