assume that the class has 80 students and that the examination period is 95 minutes in length. How many students do you expect will be unable to complete the exam in the allotted time

Number of students successful= 75

Number of students not able to complete the exam in the allotted time= 5

Step-by-step explanation:

In this question the main part is missing .The given statement is the sub part of the problem .

Suppose the main part is

The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes.

If the main part was given like this only then we could do the following calculations.

So from above the

Population mean = μ= 80

Population Standard deviation =σ= 10 mins

Sample mean = x`= 95

Sample size= n= 80

Now first we calculate the z= score

z= x`-μ/σ

z= 95-80/10= 1.5

From the z- table we find the P (z< 1.5)= 0.9332

Now we have to find the number of students who need to complete the exam in the allotted time

Number of students successful= np= 80 * 0.9332= 74.656= 75

Number of students not able to complete the exam in the allotted time= 80-75= 5

These answers are based on the main part supposed to be as added just to explain how it will be calculated.

There may be any discrepancy with the original question.

do you have an easier question cause this shh is hard like theheck

step-by-step explanation:

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.