Can the remainder in a division problem ever equal the divisor? why or why not

The answer is no because when we basically  divide the number  , we always choose the result of the division [quotient] to be like the largest whole number of divisors possible to fit into the thing being divided [dividend]  , when we realized that the divisor doesn't exactly divide   the dividend  , we set things up so the leftover falls short . Then we use fractions or decimals , one can put the remainder over the divisor , and the result is a mixed number.
Anyways a remainder is always less than a divisor .

(-14+3/2b) - (1+8/2b) = -5 -5/2b(-10+b) + (7b-5) = 8b-15(7/2b-3) - (8+6b) = -5/2b-11(5+2b) + (2b+3/2) = 4b+ 13/2